Base | Representation |
---|---|
bin | 111011110110111010011… |
… | …110000011001111100101 |
3 | 112120020102202122110020211 |
4 | 323312322132003033211 |
5 | 1014343232002021203 |
6 | 12425401521455421 |
7 | 603120121211434 |
oct | 73667236031745 |
9 | 15506382573224 |
10 | 4113412142053 |
11 | 1346540a10595 |
12 | 5652594a1571 |
13 | 23ab7c1accb6 |
14 | 10313977111b |
15 | 71eec907c6d |
hex | 3bdba7833e5 |
4113412142053 has 2 divisors, whose sum is σ = 4113412142054. Its totient is φ = 4113412142052.
The previous prime is 4113412142003. The next prime is 4113412142101. The reversal of 4113412142053 is 3502412143114.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2619888620449 + 1493523521604 = 1618607^2 + 1222098^2 .
It is a cyclic number.
It is not a de Polignac number, because 4113412142053 - 29 = 4113412141541 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4113412142003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056706071026 + 2056706071027.
It is an arithmetic number, because the mean of its divisors is an integer number (2056706071027).
Almost surely, 24113412142053 is an apocalyptic number.
It is an amenable number.
4113412142053 is a deficient number, since it is larger than the sum of its proper divisors (1).
4113412142053 is an equidigital number, since it uses as much as digits as its factorization.
4113412142053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 4113412142053 its reverse (3502412143114), we get a palindrome (7615824285167).
The spelling of 4113412142053 in words is "four trillion, one hundred thirteen billion, four hundred twelve million, one hundred forty-two thousand, fifty-three".
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