4113442340341 has 2 divisors, whose sum is σ = 4113442340342. Its totient is φ = 4113442340340.

The previous prime is 4113442340323. The next prime is 4113442340353. The reversal of 4113442340341 is 1430432443114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4061877468100 + 51564872241 = 2015410^2 + 227079^2 .

It is a cyclic number.

It is not a de Polignac number, because 4113442340341 - 2¹⁵ = 4113442307573 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4113442340297 and 4113442340306.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4113442341341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056721170170 + 2056721170171.

It is an arithmetic number, because the mean of its divisors is an integer number (2056721170171).

Almost surely, 2^{4113442340341} is an apocalyptic number.

It is an amenable number.

4113442340341 is a deficient number, since it is larger than the sum of its proper divisors (1).

4113442340341 is an equidigital number, since it uses as much as digits as its factorization.

4113442340341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 55296, while the sum is 34.

Adding to 4113442340341 its reverse (1430432443114), we get a palindrome (5543874783455).

The spelling of 4113442340341 in words is "four trillion, one hundred thirteen billion, four hundred forty-two million, three hundred forty thousand, three hundred forty-one".