41140110412132 has 24 divisors (see below), whose sum is σ = 72741395442240. Its totient is φ = 20357867402400.

The previous prime is 41140110412091. The next prime is 41140110412189. The reversal of 41140110412132 is 23121401104114.

41140110412132 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 41140110412097 and 41140110412106.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 126441178 + ... + 126766129.

It is an arithmetic number, because the mean of its divisors is an integer number (3030891476760).

Almost surely, 2^{41140110412132} is an apocalyptic number.

It is an amenable number.

41140110412132 is a deficient number, since it is larger than the sum of its proper divisors (31601285030108).

41140110412132 is a wasteful number, since it uses less digits than its factorization.

41140110412132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 253207731 (or 253207729 counting only the distinct ones).

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 41140110412132 its reverse (23121401104114), we get a palindrome (64261511516246).

The spelling of 41140110412132 in words is "forty-one trillion, one hundred forty billion, one hundred ten million, four hundred twelve thousand, one hundred thirty-two".