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4114114100101 is a prime number
BaseRepresentation
bin111011110111100100010…
…011110011101110000101
3112120022020200111121200001
4323313210103303232011
51014401201202200401
612425555315121301
7603143403566365
oct73674423635605
915508220447601
104114114100101
111346871178005
125654145a3231
1323ac617566a5
141031a4a989a5
157203e365601
hex3bde44f3b85

4114114100101 has 2 divisors, whose sum is σ = 4114114100102. Its totient is φ = 4114114100100.

The previous prime is 4114114100059. The next prime is 4114114100177. The reversal of 4114114100101 is 1010014114114.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2717061019201 + 1397053080900 = 1648351^2 + 1181970^2 .

It is a cyclic number.

It is not a de Polignac number, because 4114114100101 - 27 = 4114114099973 is a prime.

It is a super-2 number, since 2×41141141001012 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4114114110101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2057057050050 + 2057057050051.

It is an arithmetic number, because the mean of its divisors is an integer number (2057057050051).

Almost surely, 24114114100101 is an apocalyptic number.

It is an amenable number.

4114114100101 is a deficient number, since it is larger than the sum of its proper divisors (1).

4114114100101 is an equidigital number, since it uses as much as digits as its factorization.

4114114100101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64, while the sum is 19.

Adding to 4114114100101 its reverse (1010014114114), we get a palindrome (5124128214215).

The spelling of 4114114100101 in words is "four trillion, one hundred fourteen billion, one hundred fourteen million, one hundred thousand, one hundred one".