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4114123012303 is a prime number
BaseRepresentation
bin111011110111100100110…
…101110011100011001111
3112120022021022021101220121
4323313210311303203033
51014401210442343203
612430000234125411
7603143542415443
oct73674465634317
915508238241817
104114123012303
111346876204967
12565417580867
1323ac63557095
141031a5d38823
15720400260bd
hex3bde4d738cf

4114123012303 has 2 divisors, whose sum is σ = 4114123012304. Its totient is φ = 4114123012302.

The previous prime is 4114123012277. The next prime is 4114123012313. The reversal of 4114123012303 is 3032103214114.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4114123012303 is a prime.

It is a super-2 number, since 2×41141230123032 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4114123012313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2057061506151 + 2057061506152.

It is an arithmetic number, because the mean of its divisors is an integer number (2057061506152).

Almost surely, 24114123012303 is an apocalyptic number.

4114123012303 is a deficient number, since it is larger than the sum of its proper divisors (1).

4114123012303 is an equidigital number, since it uses as much as digits as its factorization.

4114123012303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 4114123012303 its reverse (3032103214114), we get a palindrome (7146226226417).

The spelling of 4114123012303 in words is "four trillion, one hundred fourteen billion, one hundred twenty-three million, twelve thousand, three hundred three".