4114130232031 has 2 divisors, whose sum is σ = 4114130232032. Its totient is φ = 4114130232030.

The previous prime is 4114130232013. The next prime is 4114130232061. The reversal of 4114130232031 is 1302320314114.

Together with previous prime (4114130232013) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4114130232031 - 2¹¹ = 4114130229983 is a prime.

It is a super-2 number, since 2×4114130232031² (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4114130231987 and 4114130232005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4114130232061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2057065116015 + 2057065116016.

It is an arithmetic number, because the mean of its divisors is an integer number (2057065116016).

Almost surely, 2^{4114130232031} is an apocalyptic number.

4114130232031 is a deficient number, since it is larger than the sum of its proper divisors (1).

4114130232031 is an equidigital number, since it uses as much as digits as its factorization.

4114130232031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 4114130232031 its reverse (1302320314114), we get a palindrome (5416450546145).

The spelling of 4114130232031 in words is "four trillion, one hundred fourteen billion, one hundred thirty million, two hundred thirty-two thousand, thirty-one".