Base | Representation |
---|---|
bin | 1011111110010101001… |
… | …10101101111100011101 |
3 | 1110022221122021100002121 |
4 | 11333022212231330131 |
5 | 23220042241243123 |
6 | 513000524422541 |
7 | 41503253066635 |
oct | 5771246557435 |
9 | 1408848240077 |
10 | 411421040413 |
11 | 1495344a7079 |
12 | 678a00a7a51 |
13 | 2ca48863116 |
14 | 15cacd536c5 |
15 | aa7e40575d |
hex | 5fca9adf1d |
411421040413 has 2 divisors, whose sum is σ = 411421040414. Its totient is φ = 411421040412.
The previous prime is 411421040389. The next prime is 411421040431. The reversal of 411421040413 is 314040124114.
Together with next prime (411421040431) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 393747465049 + 17673575364 = 627493^2 + 132942^2 .
It is a cyclic number.
It is not a de Polignac number, because 411421040413 - 213 = 411421032221 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (411421740413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205710520206 + 205710520207.
It is an arithmetic number, because the mean of its divisors is an integer number (205710520207).
Almost surely, 2411421040413 is an apocalyptic number.
It is an amenable number.
411421040413 is a deficient number, since it is larger than the sum of its proper divisors (1).
411421040413 is an equidigital number, since it uses as much as digits as its factorization.
411421040413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 411421040413 its reverse (314040124114), we get a palindrome (725461164527).
The spelling of 411421040413 in words is "four hundred eleven billion, four hundred twenty-one million, forty thousand, four hundred thirteen".
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