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4114236370001 is a prime number
BaseRepresentation
bin111011110111101011100…
…110001110110001010001
3112120022120012120120102212
4323313223212032301101
51014401424002320001
612430015403521505
7603146420063402
oct73675346166121
915508505516385
104114236370001
11134692419a20a
12565449529295
1323ac80b96844
141031b70059a9
1572049e687bb
hex3bdeb98ec51

4114236370001 has 2 divisors, whose sum is σ = 4114236370002. Its totient is φ = 4114236370000.

The previous prime is 4114236369961. The next prime is 4114236370003. The reversal of 4114236370001 is 1000736324114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2100902403601 + 2013333966400 = 1449449^2 + 1418920^2 .

It is a cyclic number.

It is not a de Polignac number, because 4114236370001 - 218 = 4114236107857 is a prime.

It is a Sophie Germain prime.

Together with 4114236370003, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 4114236370001.

It is not a weakly prime, because it can be changed into another prime (4114236370003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2057118185000 + 2057118185001.

It is an arithmetic number, because the mean of its divisors is an integer number (2057118185001).

Almost surely, 24114236370001 is an apocalyptic number.

It is an amenable number.

4114236370001 is a deficient number, since it is larger than the sum of its proper divisors (1).

4114236370001 is an equidigital number, since it uses as much as digits as its factorization.

4114236370001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12096, while the sum is 32.

The spelling of 4114236370001 in words is "four trillion, one hundred fourteen billion, two hundred thirty-six million, three hundred seventy thousand, one".