411543354011 has 2 divisors, whose sum is σ = 411543354012. Its totient is φ = 411543354010.

The previous prime is 411543353993. The next prime is 411543354043. The reversal of 411543354011 is 110453345114.

It is an a-pointer prime, because the next prime (411543354043) can be obtained adding 411543354011 to its sum of digits (32).

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-411543354011 is a prime.

It is not a weakly prime, because it can be changed into another prime (411543554011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205771677005 + 205771677006.

It is an arithmetic number, because the mean of its divisors is an integer number (205771677006).

Almost surely, 2^411543354011 is an apocalyptic number.

411543354011 is a deficient number, since it is larger than the sum of its proper divisors (1).

411543354011 is an equidigital number, since it uses as much as digits as its factorization.

411543354011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 32.

Adding to 411543354011 its reverse (110453345114), we get a palindrome (521996699125).

The spelling of 411543354011 in words is "four hundred eleven billion, five hundred forty-three million, three hundred fifty-four thousand, eleven".