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4116066551 is a prime number
BaseRepresentation
bin1111010101010110…
…0011000011110111
3101121212002211211022
43311111203003313
531412203112201
61520233331355
7203666663012
oct36525430367
911555084738
104116066551
1118224597a3
1296a566b5b
1350799c14c
142b0928379
1519155041b
hexf55630f7

4116066551 has 2 divisors, whose sum is σ = 4116066552. Its totient is φ = 4116066550.

The previous prime is 4116066527. The next prime is 4116066553. The reversal of 4116066551 is 1556606114.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4116066551 is a prime.

It is a super-2 number, since 2×41160665512 = 33884007704522071202, which contains 22 as substring.

Together with 4116066553, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4116066553) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2058033275 + 2058033276.

It is an arithmetic number, because the mean of its divisors is an integer number (2058033276).

Almost surely, 24116066551 is an apocalyptic number.

4116066551 is a deficient number, since it is larger than the sum of its proper divisors (1).

4116066551 is an equidigital number, since it uses as much as digits as its factorization.

4116066551 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21600, while the sum is 35.

The square root of 4116066551 is about 64156.5783922428. The cubic root of 4116066551 is about 1602.6085769292.

The spelling of 4116066551 in words is "four billion, one hundred sixteen million, sixty-six thousand, five hundred fifty-one".