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4117099999981 is a prime number
BaseRepresentation
bin111011111010010110010…
…010000111001011101101
3112120120221210000001021111
4323322112102013023231
51014423310044444411
612431211501232021
7603310401405013
oct73722622071355
915516853001244
104117099999981
111348063687861
12565b08562611
1323b319242057
141033a94708b3
1572166571721
hex3be964872ed

4117099999981 has 2 divisors, whose sum is σ = 4117099999982. Its totient is φ = 4117099999980.

The previous prime is 4117099999979. The next prime is 4117100000017. The reversal of 4117099999981 is 1899999907114.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3915827534025 + 201272465956 = 1978845^2 + 448634^2 .

It is a cyclic number.

It is not a de Polignac number, because 4117099999981 - 21 = 4117099999979 is a prime.

It is a super-2 number, since 2×41170999999812 (a number of 26 digits) contains 22 as substring.

Together with 4117099999979, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 4117099999898 and 4117099999907.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4117099999781) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2058549999990 + 2058549999991.

It is an arithmetic number, because the mean of its divisors is an integer number (2058549999991).

Almost surely, 24117099999981 is an apocalyptic number.

It is an amenable number.

4117099999981 is a deficient number, since it is larger than the sum of its proper divisors (1).

4117099999981 is an equidigital number, since it uses as much as digits as its factorization.

4117099999981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 119042784, while the sum is 76.

The spelling of 4117099999981 in words is "four trillion, one hundred seventeen billion, ninety-nine million, nine hundred ninety-nine thousand, nine hundred eighty-one".