Base | Representation |
---|---|
bin | 111011111100000100100… |
… | …100010011110111110011 |
3 | 112120202201201121012202212 |
4 | 323330010210103313303 |
5 | 1014441102231424212 |
6 | 12432115235002335 |
7 | 603404266400444 |
oct | 73740444236763 |
9 | 15522651535685 |
10 | 4118950264307 |
11 | 134892305282a |
12 | 5663441393ab |
13 | 23b552680908 |
14 | 1035030ad2cb |
15 | 72223c07e22 |
hex | 3bf04913df3 |
4118950264307 has 2 divisors, whose sum is σ = 4118950264308. Its totient is φ = 4118950264306.
The previous prime is 4118950264271. The next prime is 4118950264309. The reversal of 4118950264307 is 7034620598114.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4118950264307 - 210 = 4118950263283 is a prime.
Together with 4118950264309, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (4118950264309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2059475132153 + 2059475132154.
It is an arithmetic number, because the mean of its divisors is an integer number (2059475132154).
It is a 2-persistent number, because it is pandigital, and so is 2⋅4118950264307 = 8237900528614, but 3⋅4118950264307 = 12356850792921 is not.
Almost surely, 24118950264307 is an apocalyptic number.
4118950264307 is a deficient number, since it is larger than the sum of its proper divisors (1).
4118950264307 is an equidigital number, since it uses as much as digits as its factorization.
4118950264307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1451520, while the sum is 50.
The spelling of 4118950264307 in words is "four trillion, one hundred eighteen billion, nine hundred fifty million, two hundred sixty-four thousand, three hundred seven".
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