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4120112314141 is a prime number
BaseRepresentation
bin111011111101001001110…
…101001011011100011101
3112120212201201012110110121
4323331021311023130131
51020000442223023031
612432430425434541
7603445136556025
oct73751165133435
915525651173417
104120112314141
111349369a98a9a
1256660933ba51
1323b6a9348575
141035b3560a85
1572290c49011
hex3bf49d4b71d

4120112314141 has 2 divisors, whose sum is σ = 4120112314142. Its totient is φ = 4120112314140.

The previous prime is 4120112314121. The next prime is 4120112314169. The reversal of 4120112314141 is 1414132110214.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3852250171225 + 267862142916 = 1962715^2 + 517554^2 .

It is a cyclic number.

It is not a de Polignac number, because 4120112314141 - 217 = 4120112183069 is a prime.

It is a super-2 number, since 2×41201123141412 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4120112314121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2060056157070 + 2060056157071.

It is an arithmetic number, because the mean of its divisors is an integer number (2060056157071).

Almost surely, 24120112314141 is an apocalyptic number.

It is an amenable number.

4120112314141 is a deficient number, since it is larger than the sum of its proper divisors (1).

4120112314141 is an equidigital number, since it uses as much as digits as its factorization.

4120112314141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 4120112314141 its reverse (1414132110214), we get a palindrome (5534244424355).

The spelling of 4120112314141 in words is "four trillion, one hundred twenty billion, one hundred twelve million, three hundred fourteen thousand, one hundred forty-one".