4120141 has 2 divisors, whose sum is σ = 4120142. Its totient is φ = 4120140.

The previous prime is 4120133. The next prime is 4120159. The reversal of 4120141 is 1410214.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3822025 + 298116 = 1955^2 + 546^2 .

It is a cyclic number.

It is not a de Polignac number, because 4120141 - 2³ = 4120133 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4120111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2060070 + 2060071.

It is an arithmetic number, because the mean of its divisors is an integer number (2060071).

Almost surely, 2^4120141 is an apocalyptic number.

It is an amenable number.

4120141 is a deficient number, since it is larger than the sum of its proper divisors (1).

4120141 is an equidigital number, since it uses as much as digits as its factorization.

4120141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32, while the sum is 13.

The square root of 4120141 is about 2029.8130455783. The cubic root of 4120141 is about 160.3137204074.

Adding to 4120141 its reverse (1410214), we get a palindrome (5530355).

The spelling of 4120141 in words is "four million, one hundred twenty thousand, one hundred forty-one".