Base | Representation |
---|---|
bin | 10010101111001000110000… |
… | …10111101011110100110110 |
3 | 12101212212122022200112120210 |
4 | 21113210120113223310312 |
5 | 20400023224203220114 |
6 | 223343541253410250 |
7 | 11451514500431355 |
oct | 1127443027536466 |
9 | 171785568615523 |
10 | 41202030132534 |
11 | 12145756969847 |
12 | 4755290639986 |
13 | 19cb447649c0b |
14 | a262904a399c |
15 | 4b6b5cc6d259 |
hex | 2579185ebd36 |
41202030132534 has 32 divisors (see below), whose sum is σ = 85989052387584. Its totient is φ = 13136542008480.
The previous prime is 41202030132521. The next prime is 41202030132581. The reversal of 41202030132534 is 43523103020214.
It is a super-2 number, since 2×412020301325342 (a number of 28 digits) contains 22 as substring.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1592664 + ... + 9216324.
It is an arithmetic number, because the mean of its divisors is an integer number (2687157887112).
Almost surely, 241202030132534 is an apocalyptic number.
41202030132534 is an abundant number, since it is smaller than the sum of its proper divisors (44787022255050).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
41202030132534 is a wasteful number, since it uses less digits than its factorization.
41202030132534 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7662852.
The product of its (nonzero) digits is 17280, while the sum is 30.
Adding to 41202030132534 its reverse (43523103020214), we get a palindrome (84725133152748).
The spelling of 41202030132534 in words is "forty-one trillion, two hundred two billion, thirty million, one hundred thirty-two thousand, five hundred thirty-four".
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