Base | Representation |
---|---|
bin | 111011111101010110111… |
… | …011010101100101011111 |
3 | 112120220022000122022012002 |
4 | 323331112323111211133 |
5 | 1020001420000013401 |
6 | 12432504315032515 |
7 | 603453445256633 |
oct | 73752673254537 |
9 | 15526260568162 |
10 | 4120332032351 |
11 | 1349472019597 |
12 | 56666aa3b73b |
13 | 23b712a17942 |
14 | 1035d47d6dc3 |
15 | 722a519aa6b |
hex | 3bf56ed595f |
4120332032351 has 2 divisors, whose sum is σ = 4120332032352. Its totient is φ = 4120332032350.
The previous prime is 4120332032329. The next prime is 4120332032423. The reversal of 4120332032351 is 1532302330214.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4120332032351 is a prime.
It is a super-3 number, since 3×41203320323513 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4120332031351) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2060166016175 + 2060166016176.
It is an arithmetic number, because the mean of its divisors is an integer number (2060166016176).
Almost surely, 24120332032351 is an apocalyptic number.
4120332032351 is a deficient number, since it is larger than the sum of its proper divisors (1).
4120332032351 is an equidigital number, since it uses as much as digits as its factorization.
4120332032351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12960, while the sum is 29.
Adding to 4120332032351 its reverse (1532302330214), we get a palindrome (5652634362565).
The spelling of 4120332032351 in words is "four trillion, one hundred twenty billion, three hundred thirty-two million, thirty-two thousand, three hundred fifty-one".
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