Base | Representation |
---|---|
bin | 100110011000010100… |
… | …110100110000101001 |
3 | 10221101000110020000021 |
4 | 212120110310300221 |
5 | 1133344314121411 |
6 | 30533131440441 |
7 | 2656141532356 |
oct | 463024646051 |
9 | 127330406007 |
10 | 41210301481 |
11 | 165281604a8 |
12 | 7ba12b6121 |
13 | 3b69a4289b |
14 | 1dcd21d62d |
15 | 1112da9a71 |
hex | 998534c29 |
41210301481 has 2 divisors, whose sum is σ = 41210301482. Its totient is φ = 41210301480.
The previous prime is 41210301479. The next prime is 41210301581. The reversal of 41210301481 is 18410301214.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 27139597081 + 14070704400 = 164741^2 + 118620^2 .
It is a cyclic number.
It is not a de Polignac number, because 41210301481 - 21 = 41210301479 is a prime.
It is a super-2 number, since 2×412103014812 (a number of 22 digits) contains 22 as substring.
Together with 41210301479, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (41210301581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20605150740 + 20605150741.
It is an arithmetic number, because the mean of its divisors is an integer number (20605150741).
Almost surely, 241210301481 is an apocalyptic number.
It is an amenable number.
41210301481 is a deficient number, since it is larger than the sum of its proper divisors (1).
41210301481 is an equidigital number, since it uses as much as digits as its factorization.
41210301481 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 41210301481 its reverse (18410301214), we get a palindrome (59620602695).
The spelling of 41210301481 in words is "forty-one billion, two hundred ten million, three hundred one thousand, four hundred eighty-one".
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