Base | Representation |
---|---|
bin | 10010101111111101000100… |
… | …01111011100011100111101 |
3 | 12101222120010110121122102022 |
4 | 21113332202033130130331 |
5 | 20401003232414010442 |
6 | 223404504043405525 |
7 | 11453530431226001 |
oct | 1127764217343475 |
9 | 171876113548368 |
10 | 41230113031997 |
11 | 12156657a3786a |
12 | 475a8095238a5 |
13 | 1a00ca17a19a6 |
14 | a27796072701 |
15 | 4b775340c3d2 |
hex | 257fa23dc73d |
41230113031997 has 2 divisors, whose sum is σ = 41230113031998. Its totient is φ = 41230113031996.
The previous prime is 41230113031957. The next prime is 41230113032029. The reversal of 41230113031997 is 79913031103214.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 39820719053956 + 1409393978041 = 6310366^2 + 1187179^2 .
It is a cyclic number.
It is not a de Polignac number, because 41230113031997 - 214 = 41230113015613 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41230113031927) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20615056515998 + 20615056515999.
It is an arithmetic number, because the mean of its divisors is an integer number (20615056515999).
Almost surely, 241230113031997 is an apocalyptic number.
It is an amenable number.
41230113031997 is a deficient number, since it is larger than the sum of its proper divisors (1).
41230113031997 is an equidigital number, since it uses as much as digits as its factorization.
41230113031997 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 122472, while the sum is 44.
The spelling of 41230113031997 in words is "forty-one trillion, two hundred thirty billion, one hundred thirteen million, thirty-one thousand, nine hundred ninety-seven".
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