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4123044120101 is a prime number
BaseRepresentation
bin111011111111111000100…
…101001000011000100101
3112121011022000220122011112
4323333320211020120211
51020022443243320401
612434033400314405
7603610606526204
oct73777045103045
915534260818145
104123044120101
11134a633a11225
125670a7172a05
1323ba558742aa
141037b0a9523b
15723b331c3bb
hex3bff8948625

4123044120101 has 2 divisors, whose sum is σ = 4123044120102. Its totient is φ = 4123044120100.

The previous prime is 4123044120073. The next prime is 4123044120103. The reversal of 4123044120101 is 1010214403214.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3053162128900 + 1069881991201 = 1747330^2 + 1034351^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4123044120101 is a prime.

Together with 4123044120103, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4123044120103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2061522060050 + 2061522060051.

It is an arithmetic number, because the mean of its divisors is an integer number (2061522060051).

Almost surely, 24123044120101 is an apocalyptic number.

It is an amenable number.

4123044120101 is a deficient number, since it is larger than the sum of its proper divisors (1).

4123044120101 is an equidigital number, since it uses as much as digits as its factorization.

4123044120101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 4123044120101 its reverse (1010214403214), we get a palindrome (5133258523315).

The spelling of 4123044120101 in words is "four trillion, one hundred twenty-three billion, forty-four million, one hundred twenty thousand, one hundred one".