Base | Representation |
---|---|
bin | 10010101111111111011101… |
… | …11100111000000111000111 |
3 | 12101222200110011021220121001 |
4 | 21113333232330320013013 |
5 | 20401013401400311213 |
6 | 223405235500034131 |
7 | 11453604346322665 |
oct | 1127775674700707 |
9 | 171880404256531 |
10 | 41231400010183 |
11 | 121571584505a9 |
12 | 475ab08532947 |
13 | 1a011482ca846 |
14 | a27878d63c35 |
15 | 4b77cb3c91dd |
hex | 257feef381c7 |
41231400010183 has 2 divisors, whose sum is σ = 41231400010184. Its totient is φ = 41231400010182.
The previous prime is 41231400010181. The next prime is 41231400010279. The reversal of 41231400010183 is 38101000413214.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 41231400010183 - 21 = 41231400010181 is a prime.
Together with 41231400010181, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41231400010181) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20615700005091 + 20615700005092.
It is an arithmetic number, because the mean of its divisors is an integer number (20615700005092).
Almost surely, 241231400010183 is an apocalyptic number.
41231400010183 is a deficient number, since it is larger than the sum of its proper divisors (1).
41231400010183 is an equidigital number, since it uses as much as digits as its factorization.
41231400010183 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 28.
Adding to 41231400010183 its reverse (38101000413214), we get a palindrome (79332400423397).
The spelling of 41231400010183 in words is "forty-one trillion, two hundred thirty-one billion, four hundred million, ten thousand, one hundred eighty-three".
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