Base | Representation |
---|---|
bin | 111011111111111110011… |
… | …011101010001100110111 |
3 | 112121011112212122201022112 |
4 | 323333332123222030313 |
5 | 1020023143412103341 |
6 | 12434051224521235 |
7 | 603613211202305 |
oct | 73777633521467 |
9 | 15534485581275 |
10 | 4123142300471 |
11 | 134a68437a627 |
12 | 56711402021b |
13 | 23ba6cccb79c |
14 | 1037bdb31275 |
15 | 723bbc62aeb |
hex | 3bffe6ea337 |
4123142300471 has 2 divisors, whose sum is σ = 4123142300472. Its totient is φ = 4123142300470.
The previous prime is 4123142300423. The next prime is 4123142300513. The reversal of 4123142300471 is 1740032413214.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4123142300471 - 210 = 4123142299447 is a prime.
It is a super-3 number, since 3×41231423004713 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4123142300071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2061571150235 + 2061571150236.
It is an arithmetic number, because the mean of its divisors is an integer number (2061571150236).
Almost surely, 24123142300471 is an apocalyptic number.
4123142300471 is a deficient number, since it is larger than the sum of its proper divisors (1).
4123142300471 is an equidigital number, since it uses as much as digits as its factorization.
4123142300471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 32.
Adding to 4123142300471 its reverse (1740032413214), we get a palindrome (5863174713685).
The spelling of 4123142300471 in words is "four trillion, one hundred twenty-three billion, one hundred forty-two million, three hundred thousand, four hundred seventy-one".
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