Base | Representation |
---|---|
bin | 111100000000111000111… |
… | …001100000000110000001 |
3 | 112121021002020101200010212 |
4 | 330000320321200012001 |
5 | 1020032201014430141 |
6 | 12434332425003505 |
7 | 603646421550302 |
oct | 74007071400601 |
9 | 15537066350125 |
10 | 4124123201921 |
11 | 1350038039388 |
12 | 567348623595 |
13 | 23bb982ac948 |
14 | 10387410a7a9 |
15 | 72427e202eb |
hex | 3c038e60181 |
4124123201921 has 2 divisors, whose sum is σ = 4124123201922. Its totient is φ = 4124123201920.
The previous prime is 4124123201911. The next prime is 4124123201923. The reversal of 4124123201921 is 1291023214214.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3735576679696 + 388546522225 = 1932764^2 + 623335^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4124123201921 is a prime.
Together with 4124123201923, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (4124123201923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2062061600960 + 2062061600961.
It is an arithmetic number, because the mean of its divisors is an integer number (2062061600961).
Almost surely, 24124123201921 is an apocalyptic number.
It is an amenable number.
4124123201921 is a deficient number, since it is larger than the sum of its proper divisors (1).
4124123201921 is an equidigital number, since it uses as much as digits as its factorization.
4124123201921 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 32.
The spelling of 4124123201921 in words is "four trillion, one hundred twenty-four billion, one hundred twenty-three million, two hundred one thousand, nine hundred twenty-one".
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