Base | Representation |
---|---|
bin | 111100000000111001100… |
… | …011111001000011011011 |
3 | 112121021010000022020022212 |
4 | 330000321203321003123 |
5 | 1020032211341023303 |
6 | 12434333503105335 |
7 | 603646615161521 |
oct | 74007143710333 |
9 | 15537100266285 |
10 | 4124134314203 |
11 | 1350043339192 |
12 | 5673502a224b |
13 | 23bb9a6a0867 |
14 | 1038757a0311 |
15 | 72428db7ad8 |
hex | 3c0398f90db |
4124134314203 has 2 divisors, whose sum is σ = 4124134314204. Its totient is φ = 4124134314202.
The previous prime is 4124134314191. The next prime is 4124134314257. The reversal of 4124134314203 is 3024134314214.
4124134314203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4124134314203 - 210 = 4124134313179 is a prime.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 4124134314203.
It is not a weakly prime, because it can be changed into another prime (4124134314283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2062067157101 + 2062067157102.
It is an arithmetic number, because the mean of its divisors is an integer number (2062067157102).
Almost surely, 24124134314203 is an apocalyptic number.
4124134314203 is a deficient number, since it is larger than the sum of its proper divisors (1).
4124134314203 is an equidigital number, since it uses as much as digits as its factorization.
4124134314203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27648, while the sum is 32.
Adding to 4124134314203 its reverse (3024134314214), we get a palindrome (7148268628417).
The spelling of 4124134314203 in words is "four trillion, one hundred twenty-four billion, one hundred thirty-four million, three hundred fourteen thousand, two hundred three".
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