4124134314281 has 2 divisors, whose sum is σ = 4124134314282. Its totient is φ = 4124134314280.

The previous prime is 4124134314257. The next prime is 4124134314283. The reversal of 4124134314281 is 1824134314214.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3020699616256 + 1103434698025 = 1738016^2 + 1050445^2 .

It is a cyclic number.

It is not a de Polignac number, because 4124134314281 - 2²⁶ = 4124067205417 is a prime.

It is a super-2 number, since 2×4124134314281² (a number of 26 digits) contains 22 as substring.

Together with 4124134314283, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (4124134314283) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2062067157140 + 2062067157141.

It is an arithmetic number, because the mean of its divisors is an integer number (2062067157141).

Almost surely, 2^{4124134314281} is an apocalyptic number.

It is an amenable number.

4124134314281 is a deficient number, since it is larger than the sum of its proper divisors (1).

4124134314281 is an equidigital number, since it uses as much as digits as its factorization.

4124134314281 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 73728, while the sum is 38.

Adding to 4124134314281 its reverse (1824134314214), we get a palindrome (5948268628495).

The spelling of 4124134314281 in words is "four trillion, one hundred twenty-four billion, one hundred thirty-four million, three hundred fourteen thousand, two hundred eighty-one".