41254113414013 has 2 divisors, whose sum is σ = 41254113414014. Its totient is φ = 41254113414012.

The previous prime is 41254113414001. The next prime is 41254113414037. The reversal of 41254113414013 is 31041431145214.

41254113414013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 27318204729124 + 13935908684889 = 5226682^2 + 3733083^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-41254113414013 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 41254113414013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41254113414053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20627056707006 + 20627056707007.

It is an arithmetic number, because the mean of its divisors is an integer number (20627056707007).

Almost surely, 2^{41254113414013} is an apocalyptic number.

It is an amenable number.

41254113414013 is a deficient number, since it is larger than the sum of its proper divisors (1).

41254113414013 is an equidigital number, since it uses as much as digits as its factorization.

41254113414013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23040, while the sum is 34.

Adding to 41254113414013 its reverse (31041431145214), we get a palindrome (72295544559227).

The spelling of 41254113414013 in words is "forty-one trillion, two hundred fifty-four billion, one hundred thirteen million, four hundred fourteen thousand, thirteen".