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41255113341053 is a prime number
BaseRepresentation
bin10010110000101011101000…
…11000000011100001111101
312102001221122210002221011202
421120111310120003201331
520401410433003403203
6223424200515025245
711455404111315263
oct1130256430034175
9172057583087152
1041255113341053
1112166216a65007
124763625b9b225
131a034570b5a81
14a28a8849a433
154b8218141388
hex25857460387d

41255113341053 has 2 divisors, whose sum is σ = 41255113341054. Its totient is φ = 41255113341052.

The previous prime is 41255113341047. The next prime is 41255113341077. The reversal of 41255113341053 is 35014331155214.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 22062767198404 + 19192346142649 = 4697102^2 + 4380907^2 .

It is a cyclic number.

It is not a de Polignac number, because 41255113341053 - 218 = 41255113078909 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 41255113340998 and 41255113341016.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41255113341553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20627556670526 + 20627556670527.

It is an arithmetic number, because the mean of its divisors is an integer number (20627556670527).

Almost surely, 241255113341053 is an apocalyptic number.

It is an amenable number.

41255113341053 is a deficient number, since it is larger than the sum of its proper divisors (1).

41255113341053 is an equidigital number, since it uses as much as digits as its factorization.

41255113341053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108000, while the sum is 38.

Adding to 41255113341053 its reverse (35014331155214), we get a palindrome (76269444496267).

The spelling of 41255113341053 in words is "forty-one trillion, two hundred fifty-five billion, one hundred thirteen million, three hundred forty-one thousand, fifty-three".