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41255259917 is a prime number
BaseRepresentation
bin100110011011000000…
…010100111100001101
310221111011001100101112
4212123000110330031
51133442321304132
630541415221405
72660225631464
oct463300247415
9127434040345
1041255259917
1116550578433
127bb4377865
133b76154301
141dd51a39db
151116cdaab2
hex99b014f0d

41255259917 has 2 divisors, whose sum is σ = 41255259918. Its totient is φ = 41255259916.

The previous prime is 41255259883. The next prime is 41255259967. The reversal of 41255259917 is 71995255214.

It is an a-pointer prime, because the next prime (41255259967) can be obtained adding 41255259917 to its sum of digits (50).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 33631525321 + 7623734596 = 183389^2 + 87314^2 .

It is a cyclic number.

It is not a de Polignac number, because 41255259917 - 26 = 41255259853 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41255259967) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20627629958 + 20627629959.

It is an arithmetic number, because the mean of its divisors is an integer number (20627629959).

Almost surely, 241255259917 is an apocalyptic number.

It is an amenable number.

41255259917 is a deficient number, since it is larger than the sum of its proper divisors (1).

41255259917 is an equidigital number, since it uses as much as digits as its factorization.

41255259917 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1134000, while the sum is 50.

The spelling of 41255259917 in words is "forty-one billion, two hundred fifty-five million, two hundred fifty-nine thousand, nine hundred seventeen".