Base | Representation |
---|---|
bin | 1111010111111110… |
… | …1011111110110101 |
3 | 101122121220001220021 |
4 | 3311333223332311 |
5 | 31423020110031 |
6 | 1521310205141 |
7 | 204162611554 |
oct | 36577537665 |
9 | 11577801807 |
10 | 4127113141 |
11 | 1828714208 |
12 | 9721b37b1 |
13 | 50a0691a8 |
14 | 2b21a1d9b |
15 | 1924d3511 |
hex | f5febfb5 |
4127113141 has 2 divisors, whose sum is σ = 4127113142. Its totient is φ = 4127113140.
The previous prime is 4127113121. The next prime is 4127113213. The reversal of 4127113141 is 1413117214.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3059196100 + 1067917041 = 55310^2 + 32679^2 .
It is a cyclic number.
It is not a de Polignac number, because 4127113141 - 231 = 1979629493 is a prime.
It is a super-2 number, since 2×41271131412 = 34066125757229771762, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4127113121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2063556570 + 2063556571.
It is an arithmetic number, because the mean of its divisors is an integer number (2063556571).
Almost surely, 24127113141 is an apocalyptic number.
It is an amenable number.
4127113141 is a deficient number, since it is larger than the sum of its proper divisors (1).
4127113141 is an equidigital number, since it uses as much as digits as its factorization.
4127113141 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 672, while the sum is 25.
The square root of 4127113141 is about 64242.6115674013. The cubic root of 4127113141 is about 1604.0409757144.
The spelling of 4127113141 in words is "four billion, one hundred twenty-seven million, one hundred thirteen thousand, one hundred forty-one".
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