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412906371497 is a prime number
BaseRepresentation
bin1100000001000110010…
…00110011100110101001
31110110210011011222021222
412000203020303212221
523231113012341442
6513404144311425
741555130151154
oct6004310634651
91413704158258
10412906371497
1114a126978324
1268035612575
132cc244ba659
1415db0318c9b
15ab19a038d2
hex60232339a9

412906371497 has 2 divisors, whose sum is σ = 412906371498. Its totient is φ = 412906371496.

The previous prime is 412906371463. The next prime is 412906371499. The reversal of 412906371497 is 794173609214.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 386273437081 + 26632934416 = 621509^2 + 163196^2 .

It is a cyclic number.

It is not a de Polignac number, because 412906371497 - 228 = 412637936041 is a prime.

Together with 412906371499, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (412906371499) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206453185748 + 206453185749.

It is an arithmetic number, because the mean of its divisors is an integer number (206453185749).

Almost surely, 2412906371497 is an apocalyptic number.

It is an amenable number.

412906371497 is a deficient number, since it is larger than the sum of its proper divisors (1).

412906371497 is an equidigital number, since it uses as much as digits as its factorization.

412906371497 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2286144, while the sum is 53.

The spelling of 412906371497 in words is "four hundred twelve billion, nine hundred six million, three hundred seventy-one thousand, four hundred ninety-seven".