Base | Representation |
---|---|
bin | 100110011101101100… |
… | …100001111101001001 |
3 | 10221121021222210200021 |
4 | 212131230201331021 |
5 | 1134040400330433 |
6 | 30550110540441 |
7 | 2661314424154 |
oct | 463554417511 |
9 | 127537883607 |
10 | 41300401993 |
11 | 16574000334 |
12 | 8007507721 |
13 | 3b825cb4b6 |
14 | 1ddb194c9b |
15 | 111ac5622d |
hex | 99db21f49 |
41300401993 has 2 divisors, whose sum is σ = 41300401994. Its totient is φ = 41300401992.
The previous prime is 41300401991. The next prime is 41300402041. The reversal of 41300401993 is 39910400314.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 40641350409 + 659051584 = 201597^2 + 25672^2 .
It is a cyclic number.
It is not a de Polignac number, because 41300401993 - 21 = 41300401991 is a prime.
Together with 41300401991, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (41300401991) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20650200996 + 20650200997.
It is an arithmetic number, because the mean of its divisors is an integer number (20650200997).
Almost surely, 241300401993 is an apocalyptic number.
It is an amenable number.
41300401993 is a deficient number, since it is larger than the sum of its proper divisors (1).
41300401993 is an equidigital number, since it uses as much as digits as its factorization.
41300401993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11664, while the sum is 34.
The spelling of 41300401993 in words is "forty-one billion, three hundred million, four hundred one thousand, nine hundred ninety-three".
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