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413004020202 = 23229791195441
BaseRepresentation
bin1100000001010001111…
…01010011100111101010
31110111000221221001010200
412000220331103213222
523231313012121302
6513421553253030
741560424151234
oct6005075234752
91414027831120
10413004020202
1114a177003234
1268062264176
132cc3b7b9b57
1415dbd297254
15ab2339181c
hex6028f539ea

413004020202 has 24 divisors (see below), whose sum is σ = 925698667140. Its totient is φ = 132920833920.

The previous prime is 413004020189. The next prime is 413004020257. The reversal of 413004020202 is 202020400314.

It can be written as a sum of positive squares in 2 ways, for example, as 355968550161 + 57035470041 = 596631^2 + 238821^2 .

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 395597199 + ... + 395598242.

Almost surely, 2413004020202 is an apocalyptic number.

413004020202 is an abundant number, since it is smaller than the sum of its proper divisors (512694646938).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

413004020202 is a wasteful number, since it uses less digits than its factorization.

413004020202 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 791195478 (or 791195475 counting only the distinct ones).

The product of its (nonzero) digits is 384, while the sum is 18.

Adding to 413004020202 its reverse (202020400314), we get a palindrome (615024420516).

The spelling of 413004020202 in words is "four hundred thirteen billion, four million, twenty thousand, two hundred two".

Divisors: 1 2 3 6 9 18 29 58 87 174 261 522 791195441 1582390882 2373586323 4747172646 7120758969 14241517938 22944667789 45889335578 68834003367 137668006734 206502010101 413004020202