Base | Representation |
---|---|
bin | 111100000110011001101… |
… | …000001001101111000101 |
3 | 112121211100122210112021010 |
4 | 330012121220021233011 |
5 | 1020131310444324031 |
6 | 12441151544112433 |
7 | 604246160236353 |
oct | 74063150115705 |
9 | 15554318715233 |
10 | 4130041011141 |
11 | 13525a4532001 |
12 | 56851a465719 |
13 | 23c5cc32c0c6 |
14 | 103c760427d3 |
15 | 72672720246 |
hex | 3c199a09bc5 |
4130041011141 has 16 divisors (see below), whose sum is σ = 5729996692224. Its totient is φ = 2643933649344.
The previous prime is 4130041011043. The next prime is 4130041011191. The reversal of 4130041011141 is 1411101400314.
It is not a de Polignac number, because 4130041011141 - 215 = 4130040978373 is a prime.
It is a super-2 number, since 2×41300410111412 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4130041011191) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 276323386 + ... + 276338331.
It is an arithmetic number, because the mean of its divisors is an integer number (358124793264).
Almost surely, 24130041011141 is an apocalyptic number.
It is an amenable number.
4130041011141 is a deficient number, since it is larger than the sum of its proper divisors (1599955681083).
4130041011141 is a wasteful number, since it uses less digits than its factorization.
4130041011141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 552661820.
The product of its (nonzero) digits is 192, while the sum is 21.
Adding to 4130041011141 its reverse (1411101400314), we get a palindrome (5541142411455).
The spelling of 4130041011141 in words is "four trillion, one hundred thirty billion, forty-one million, eleven thousand, one hundred forty-one".
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