Base | Representation |
---|---|
bin | 111100000110011001101… |
… | …100000000010101001101 |
3 | 112121211100201200211210121 |
4 | 330012121230000111031 |
5 | 1020131311224134242 |
6 | 12441152021504541 |
7 | 604246201644211 |
oct | 74063154002515 |
9 | 15554321624717 |
10 | 4130042021197 |
11 | 13525a5061964 |
12 | 56851a872151 |
13 | 23c5cc5c3a81 |
14 | 103c76226941 |
15 | 7267286e667 |
hex | 3c199b0054d |
4130042021197 has 2 divisors, whose sum is σ = 4130042021198. Its totient is φ = 4130042021196.
The previous prime is 4130042021141. The next prime is 4130042021207. The reversal of 4130042021197 is 7911202400314.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3352601282121 + 777440739076 = 1831011^2 + 881726^2 .
It is a cyclic number.
It is not a de Polignac number, because 4130042021197 - 27 = 4130042021069 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4130042121197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2065021010598 + 2065021010599.
It is an arithmetic number, because the mean of its divisors is an integer number (2065021010599).
Almost surely, 24130042021197 is an apocalyptic number.
It is an amenable number.
4130042021197 is a deficient number, since it is larger than the sum of its proper divisors (1).
4130042021197 is an equidigital number, since it uses as much as digits as its factorization.
4130042021197 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 34.
The spelling of 4130042021197 in words is "four trillion, one hundred thirty billion, forty-two million, twenty-one thousand, one hundred ninety-seven".
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