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413013253551541 is a prime number
BaseRepresentation
bin101110111101000100010010…
…0010000111111010110110101
32000011100200101202122211012121
41131322020210100333112311
5413113302120402122131
64022223400325115541
7152665136305015006
oct13572104420772665
92004320352584177
10413013253551541
1110a664a3443a875
123a3a489ab58bb1
131495bca0c91c56
1473dbd3b95b1ad
1532b36510ed911
hex177a22443f5b5

413013253551541 has 2 divisors, whose sum is σ = 413013253551542. Its totient is φ = 413013253551540.

The previous prime is 413013253551499. The next prime is 413013253551559. The reversal of 413013253551541 is 145155352310314.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 409031815966225 + 3981437585316 = 20224535^2 + 1995354^2 .

It is a cyclic number.

It is not a de Polignac number, because 413013253551541 - 215 = 413013253518773 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (413013253552541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206506626775770 + 206506626775771.

It is an arithmetic number, because the mean of its divisors is an integer number (206506626775771).

Almost surely, 2413013253551541 is an apocalyptic number.

It is an amenable number.

413013253551541 is a deficient number, since it is larger than the sum of its proper divisors (1).

413013253551541 is an equidigital number, since it uses as much as digits as its factorization.

413013253551541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 540000, while the sum is 43.

The spelling of 413013253551541 in words is "four hundred thirteen trillion, thirteen billion, two hundred fifty-three million, five hundred fifty-one thousand, five hundred forty-one".