Base | Representation |
---|---|
bin | 111100000110100011111… |
… | …100001010101110001111 |
3 | 112121211210201100210211021 |
4 | 330012203330022232033 |
5 | 1020132134242431343 |
6 | 12441221044335011 |
7 | 604253361001231 |
oct | 74064374125617 |
9 | 15554721323737 |
10 | 4130214030223 |
11 | 1352683166886 |
12 | 5685683a4467 |
13 | 23c62912a668 |
14 | 103c91000251 |
15 | 726829ea0ed |
hex | 3c1a3f0ab8f |
4130214030223 has 2 divisors, whose sum is σ = 4130214030224. Its totient is φ = 4130214030222.
The previous prime is 4130214030203. The next prime is 4130214030281. The reversal of 4130214030223 is 3220304120314.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4130214030223 - 217 = 4130213899151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4130214030203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2065107015111 + 2065107015112.
It is an arithmetic number, because the mean of its divisors is an integer number (2065107015112).
Almost surely, 24130214030223 is an apocalyptic number.
4130214030223 is a deficient number, since it is larger than the sum of its proper divisors (1).
4130214030223 is an equidigital number, since it uses as much as digits as its factorization.
4130214030223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 4130214030223 its reverse (3220304120314), we get a palindrome (7350518150537).
Subtracting from 4130214030223 its reverse (3220304120314), we obtain a palindrome (909909909909).
The spelling of 4130214030223 in words is "four trillion, one hundred thirty billion, two hundred fourteen million, thirty thousand, two hundred twenty-three".
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