Base | Representation |
---|---|
bin | 111100000110100100011… |
… | …000010100111100001111 |
3 | 112121211211020020211212112 |
4 | 330012210120110330033 |
5 | 1020132143140141421 |
6 | 12441221510454235 |
7 | 604253510514614 |
oct | 74064430247417 |
9 | 15554736224775 |
10 | 4130221412111 |
11 | 1352687348a13 |
12 | 56856a96437b |
13 | 23c62a813642 |
14 | 103c91da250b |
15 | 726834a745b |
hex | 3c1a4614f0f |
4130221412111 has 2 divisors, whose sum is σ = 4130221412112. Its totient is φ = 4130221412110.
The previous prime is 4130221412089. The next prime is 4130221412113. The reversal of 4130221412111 is 1112141220314.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4130221412111 is a prime.
It is a Sophie Germain prime.
Together with 4130221412113, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4130221412113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2065110706055 + 2065110706056.
It is an arithmetic number, because the mean of its divisors is an integer number (2065110706056).
Almost surely, 24130221412111 is an apocalyptic number.
4130221412111 is a deficient number, since it is larger than the sum of its proper divisors (1).
4130221412111 is an equidigital number, since it uses as much as digits as its factorization.
4130221412111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 4130221412111 its reverse (1112141220314), we get a palindrome (5242362632425).
The spelling of 4130221412111 in words is "four trillion, one hundred thirty billion, two hundred twenty-one million, four hundred twelve thousand, one hundred eleven".
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