Base | Representation |
---|---|
bin | 100110011101110011… |
… | …111000111110101111 |
3 | 10221121102121211012111 |
4 | 212131303320332233 |
5 | 1134041344100221 |
6 | 30550220144451 |
7 | 2661340011043 |
oct | 463563707657 |
9 | 127542554174 |
10 | 41302331311 |
11 | 165750a890a |
12 | 8008098127 |
13 | 3b82b256c7 |
14 | 1ddb538023 |
15 | 111aed7be1 |
hex | 99dcf8faf |
41302331311 has 2 divisors, whose sum is σ = 41302331312. Its totient is φ = 41302331310.
The previous prime is 41302331293. The next prime is 41302331333. The reversal of 41302331311 is 11313320314.
It is an a-pointer prime, because the next prime (41302331333) can be obtained adding 41302331311 to its sum of digits (22).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 41302331311 - 27 = 41302331183 is a prime.
It is a super-2 number, since 2×413023313112 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41302337311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20651165655 + 20651165656.
It is an arithmetic number, because the mean of its divisors is an integer number (20651165656).
Almost surely, 241302331311 is an apocalyptic number.
41302331311 is a deficient number, since it is larger than the sum of its proper divisors (1).
41302331311 is an equidigital number, since it uses as much as digits as its factorization.
41302331311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 41302331311 its reverse (11313320314), we get a palindrome (52615651625).
The spelling of 41302331311 in words is "forty-one billion, three hundred two million, three hundred thirty-one thousand, three hundred eleven".
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