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413031431041 is a prime number
BaseRepresentation
bin1100000001010101001…
…01110111101110000001
31110111002212111122201221
412000222211313232001
523231342021243131
6513424412555041
741561206144225
oct6005245675601
91414085448657
10413031431041
1114a190525419
126806b482a81
132cc44396498
1415dc2b90785
15ab259a8411
hex602a977b81

413031431041 has 2 divisors, whose sum is σ = 413031431042. Its totient is φ = 413031431040.

The previous prime is 413031431017. The next prime is 413031431047. The reversal of 413031431041 is 140134130314.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 286369468225 + 126661962816 = 535135^2 + 355896^2 .

It is a cyclic number.

It is not a de Polignac number, because 413031431041 - 27 = 413031430913 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 413031430997 and 413031431015.

It is not a weakly prime, because it can be changed into another prime (413031431047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206515715520 + 206515715521.

It is an arithmetic number, because the mean of its divisors is an integer number (206515715521).

Almost surely, 2413031431041 is an apocalyptic number.

It is an amenable number.

413031431041 is a deficient number, since it is larger than the sum of its proper divisors (1).

413031431041 is an equidigital number, since it uses as much as digits as its factorization.

413031431041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 413031431041 its reverse (140134130314), we get a palindrome (553165561355).

The spelling of 413031431041 in words is "four hundred thirteen billion, thirty-one million, four hundred thirty-one thousand, forty-one".