Base | Representation |
---|---|
bin | 10010110010000101011010… |
… | …01000100111001000001111 |
3 | 12102020120001201001210002121 |
4 | 21121002231020213020033 |
5 | 20403203134404443002 |
6 | 223502251225433411 |
7 | 11462031350203444 |
oct | 1131025510471017 |
9 | 172216051053077 |
10 | 41303310234127 |
11 | 121846a9941147 |
12 | 4770a3703b867 |
13 | 1a07b68418506 |
14 | a2b13b5459cb |
15 | 4b95d9567237 |
hex | 2590ad22720f |
41303310234127 has 2 divisors, whose sum is σ = 41303310234128. Its totient is φ = 41303310234126.
The previous prime is 41303310234089. The next prime is 41303310234157. The reversal of 41303310234127 is 72143201330314.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 41303310234127 - 215 = 41303310201359 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 41303310234092 and 41303310234101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41303310234157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20651655117063 + 20651655117064.
It is an arithmetic number, because the mean of its divisors is an integer number (20651655117064).
Almost surely, 241303310234127 is an apocalyptic number.
41303310234127 is a deficient number, since it is larger than the sum of its proper divisors (1).
41303310234127 is an equidigital number, since it uses as much as digits as its factorization.
41303310234127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36288, while the sum is 34.
The spelling of 41303310234127 in words is "forty-one trillion, three hundred three billion, three hundred ten million, two hundred thirty-four thousand, one hundred twenty-seven".
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