Base | Representation |
---|---|
bin | 111100000111010101010… |
… | …000110101010100100101 |
3 | 112121220221101110012201121 |
4 | 330013111100311110211 |
5 | 1020140333112444143 |
6 | 12441435124453541 |
7 | 604313026434364 |
oct | 74072520652445 |
9 | 15556841405647 |
10 | 4131041531173 |
11 | 1352a68280567 |
12 | 56875954a2b1 |
13 | 23c72b6bbbab |
14 | 103d2cc877db |
15 | 726d04a57ed |
hex | 3c1d5435525 |
4131041531173 has 2 divisors, whose sum is σ = 4131041531174. Its totient is φ = 4131041531172.
The previous prime is 4131041531117. The next prime is 4131041531213. The reversal of 4131041531173 is 3711351401314.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3916729939329 + 214311591844 = 1979073^2 + 462938^2 .
It is a cyclic number.
It is not a de Polignac number, because 4131041531173 - 29 = 4131041530661 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4131041511173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2065520765586 + 2065520765587.
It is an arithmetic number, because the mean of its divisors is an integer number (2065520765587).
Almost surely, 24131041531173 is an apocalyptic number.
It is an amenable number.
4131041531173 is a deficient number, since it is larger than the sum of its proper divisors (1).
4131041531173 is an equidigital number, since it uses as much as digits as its factorization.
4131041531173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15120, while the sum is 34.
Adding to 4131041531173 its reverse (3711351401314), we get a palindrome (7842392932487).
The spelling of 4131041531173 in words is "four trillion, one hundred thirty-one billion, forty-one million, five hundred thirty-one thousand, one hundred seventy-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •