Base | Representation |
---|---|
bin | 111100000111011010100… |
… | …010010100001110101111 |
3 | 112121221011112220220120001 |
4 | 330013122202110032233 |
5 | 1020141023240002203 |
6 | 12441452005005131 |
7 | 604315152423025 |
oct | 74073242241657 |
9 | 15557145826501 |
10 | 4131130000303 |
11 | 1353003206749 |
12 | 5687830b37a7 |
13 | 23c743b260a7 |
14 | 103d3a916715 |
15 | 726d812d91d |
hex | 3c1da8943af |
4131130000303 has 2 divisors, whose sum is σ = 4131130000304. Its totient is φ = 4131130000302.
The previous prime is 4131130000301. The next prime is 4131130000337. The reversal of 4131130000303 is 3030000311314.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4131130000303 - 21 = 4131130000301 is a prime.
Together with 4131130000301, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4131130000301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2065565000151 + 2065565000152.
It is an arithmetic number, because the mean of its divisors is an integer number (2065565000152).
Almost surely, 24131130000303 is an apocalyptic number.
4131130000303 is a deficient number, since it is larger than the sum of its proper divisors (1).
4131130000303 is an equidigital number, since it uses as much as digits as its factorization.
4131130000303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 4131130000303 its reverse (3030000311314), we get a palindrome (7161130311617).
The spelling of 4131130000303 in words is "four trillion, one hundred thirty-one billion, one hundred thirty million, three hundred three", and thus it is an aban number.
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