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41315114041 is a prime number
BaseRepresentation
bin100110011110100100…
…101001110000111001
310221122022200020210221
4212132210221300321
51134103132122131
630551354140041
72661553450345
oct463644516071
9127568606727
1041315114041
1116581339753
128010421621
133b8567ca56
141ddd104625
15111c1b0411
hex99e929c39

41315114041 has 2 divisors, whose sum is σ = 41315114042. Its totient is φ = 41315114040.

The previous prime is 41315114039. The next prime is 41315114063. The reversal of 41315114041 is 14041151314.

41315114041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 22051062016 + 19264052025 = 148496^2 + 138795^2 .

It is a cyclic number.

It is not a de Polignac number, because 41315114041 - 21 = 41315114039 is a prime.

Together with 41315114039, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 41315113997 and 41315114015.

It is not a weakly prime, because it can be changed into another prime (41315124041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20657557020 + 20657557021.

It is an arithmetic number, because the mean of its divisors is an integer number (20657557021).

Almost surely, 241315114041 is an apocalyptic number.

It is an amenable number.

41315114041 is a deficient number, since it is larger than the sum of its proper divisors (1).

41315114041 is an equidigital number, since it uses as much as digits as its factorization.

41315114041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 960, while the sum is 25.

Adding to 41315114041 its reverse (14041151314), we get a palindrome (55356265355).

The spelling of 41315114041 in words is "forty-one billion, three hundred fifteen million, one hundred fourteen thousand, forty-one".