Base | Representation |
---|---|
bin | 10010110010100101110110… |
… | …00010101000101000111000 |
3 | 12102022020000021001011020220 |
4 | 21121102323002220220320 |
5 | 20403444320143331111 |
6 | 223514251150420040 |
7 | 11463216021625404 |
oct | 1131227302505070 |
9 | 172266007034226 |
10 | 41320723417656 |
11 | 1219102515a711 |
12 | 4774296801620 |
13 | 1a096b1bb7ac7 |
14 | a2bd1005c104 |
15 | 4b9ca8158e06 |
hex | 2594bb0a8a38 |
41320723417656 has 64 divisors (see below), whose sum is σ = 107981972017920. Its totient is φ = 13151650237440.
The previous prime is 41320723417613. The next prime is 41320723417759. The reversal of 41320723417656 is 65671432702314.
It is a junction number, because it is equal to n+sod(n) for n = 41320723417599 and 41320723417608.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 65233305 + ... + 65863688.
It is an arithmetic number, because the mean of its divisors is an integer number (1687218312780).
Almost surely, 241320723417656 is an apocalyptic number.
41320723417656 is a gapful number since it is divisible by the number (46) formed by its first and last digit.
It is an amenable number.
41320723417656 is an abundant number, since it is smaller than the sum of its proper divisors (66661248600264).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
41320723417656 is a wasteful number, since it uses less digits than its factorization.
41320723417656 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 131097596 (or 131097592 counting only the distinct ones).
The product of its (nonzero) digits is 5080320, while the sum is 51.
The spelling of 41320723417656 in words is "forty-one trillion, three hundred twenty billion, seven hundred twenty-three million, four hundred seventeen thousand, six hundred fifty-six".
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