Base | Representation |
---|---|
bin | 111100001000011101100… |
… | …011010101001110010111 |
3 | 112122001001220120021122201 |
4 | 330020131203111032113 |
5 | 1020200324102334431 |
6 | 12442155331305331 |
7 | 604355054231221 |
oct | 74103543251627 |
9 | 15561056507581 |
10 | 4132254339991 |
11 | 135352a9357a8 |
12 | 568a3774b247 |
13 | 23c892a4954b |
14 | 104005d8d411 |
15 | 72751bc1461 |
hex | 3c21d8d5397 |
4132254339991 has 2 divisors, whose sum is σ = 4132254339992. Its totient is φ = 4132254339990.
The previous prime is 4132254339989. The next prime is 4132254340021. The reversal of 4132254339991 is 1999334522314.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4132254339991 - 21 = 4132254339989 is a prime.
Together with 4132254339989, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4132254339091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2066127169995 + 2066127169996.
It is an arithmetic number, because the mean of its divisors is an integer number (2066127169996).
Almost surely, 24132254339991 is an apocalyptic number.
4132254339991 is a deficient number, since it is larger than the sum of its proper divisors (1).
4132254339991 is an equidigital number, since it uses as much as digits as its factorization.
4132254339991 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6298560, while the sum is 55.
The spelling of 4132254339991 in words is "four trillion, one hundred thirty-two billion, two hundred fifty-four million, three hundred thirty-nine thousand, nine hundred ninety-one".
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