4133042241413 has 2 divisors, whose sum is σ = 4133042241414. Its totient is φ = 4133042241412.

The previous prime is 4133042241403. The next prime is 4133042241421. The reversal of 4133042241413 is 3141422403314.

4133042241413 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2563178586049 + 1569863655364 = 1600993^2 + 1252942^2 .

It is a cyclic number.

It is not a de Polignac number, because 4133042241413 - 2¹⁰ = 4133042240389 is a prime.

It is a super-3 number, since 3×4133042241413³ (a number of 39 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 4133042241413.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4133042241403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2066521120706 + 2066521120707.

It is an arithmetic number, because the mean of its divisors is an integer number (2066521120707).

Almost surely, 2^{4133042241413} is an apocalyptic number.

It is an amenable number.

4133042241413 is a deficient number, since it is larger than the sum of its proper divisors (1).

4133042241413 is an equidigital number, since it uses as much as digits as its factorization.

4133042241413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 4133042241413 its reverse (3141422403314), we get a palindrome (7274464644727).

The spelling of 4133042241413 in words is "four trillion, one hundred thirty-three billion, forty-two million, two hundred forty-one thousand, four hundred thirteen".