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41340123329957 is a prime number
BaseRepresentation
bin10010110011001001111110…
…10111011011010110100101
312102101002002021101210221022
421121210333113123112211
520404304033033024312
6223531220202100525
711464503536306444
oct1131447727332645
9172332067353838
1041340123329957
111219927a980991
124777bab7aa745
131a0b484165c5a
14a2cc30776d5b
154ba54138b172
hex25993f5db5a5

41340123329957 has 2 divisors, whose sum is σ = 41340123329958. Its totient is φ = 41340123329956.

The previous prime is 41340123329929. The next prime is 41340123330133. The reversal of 41340123329957 is 75992332104314.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 40107066324196 + 1233057005761 = 6333014^2 + 1110431^2 .

It is a cyclic number.

It is not a de Polignac number, because 41340123329957 - 228 = 41339854894501 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 41340123329899 and 41340123329908.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41340123349957) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20670061664978 + 20670061664979.

It is an arithmetic number, because the mean of its divisors is an integer number (20670061664979).

Almost surely, 241340123329957 is an apocalyptic number.

It is an amenable number.

41340123329957 is a deficient number, since it is larger than the sum of its proper divisors (1).

41340123329957 is an equidigital number, since it uses as much as digits as its factorization.

41340123329957 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4898880, while the sum is 53.

The spelling of 41340123329957 in words is "forty-one trillion, three hundred forty billion, one hundred twenty-three million, three hundred twenty-nine thousand, nine hundred fifty-seven".