Base | Representation |
---|---|
bin | 10010110011001011101000… |
… | …10010100010100011111101 |
3 | 12102101011101011011101012101 |
4 | 21121211310102202203331 |
5 | 20404312342334204323 |
6 | 223531444241105101 |
7 | 11464534540366135 |
oct | 1131456422424375 |
9 | 172334334141171 |
10 | 41341011241213 |
11 | 121996960a6842 |
12 | 47781b9028191 |
13 | 1a0b5960b9128 |
14 | a2ccb6667ac5 |
15 | 4ba5942cadad |
hex | 2599744a28fd |
41341011241213 has 2 divisors, whose sum is σ = 41341011241214. Its totient is φ = 41341011241212.
The previous prime is 41341011241141. The next prime is 41341011241241. The reversal of 41341011241213 is 31214211014314.
41341011241213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an a-pointer prime, because the next prime (41341011241241) can be obtained adding 41341011241213 to its sum of digits (28).
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 31358678413924 + 9982332827289 = 5599882^2 + 3159483^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-41341011241213 is a prime.
It is a super-2 number, since 2×413410112412132 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41341011248213) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20670505620606 + 20670505620607.
It is an arithmetic number, because the mean of its divisors is an integer number (20670505620607).
Almost surely, 241341011241213 is an apocalyptic number.
It is an amenable number.
41341011241213 is a deficient number, since it is larger than the sum of its proper divisors (1).
41341011241213 is an equidigital number, since it uses as much as digits as its factorization.
41341011241213 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 28.
Adding to 41341011241213 its reverse (31214211014314), we get a palindrome (72555222255527).
The spelling of 41341011241213 in words is "forty-one trillion, three hundred forty-one billion, eleven million, two hundred forty-one thousand, two hundred thirteen".
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