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413433936152063 is a prime number
BaseRepresentation
bin101111000000001000001011…
…0111001110000010111111111
32000012211220020212012011022222
41132000100112321300113333
5413142200200123331223
64023144532301155555
7153040421231065631
oct13600202671602777
92005756225164288
10413433936152063
1110a807390837052
123a45232485bbbb
131498c864534748
147414448930a51
1532be57364a0c8
hex1780416e705ff

413433936152063 has 2 divisors, whose sum is σ = 413433936152064. Its totient is φ = 413433936152062.

The previous prime is 413433936151993. The next prime is 413433936152089. The reversal of 413433936152063 is 360251639334314.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 413433936152063 - 28 = 413433936151807 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 413433936151996 and 413433936152014.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (413433936152563) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206716968076031 + 206716968076032.

It is an arithmetic number, because the mean of its divisors is an integer number (206716968076032).

Almost surely, 2413433936152063 is an apocalyptic number.

413433936152063 is a deficient number, since it is larger than the sum of its proper divisors (1).

413433936152063 is an equidigital number, since it uses as much as digits as its factorization.

413433936152063 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12597120, while the sum is 53.

The spelling of 413433936152063 in words is "four hundred thirteen trillion, four hundred thirty-three billion, nine hundred thirty-six million, one hundred fifty-two thousand, sixty-three".