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413441112101 is a prime number
BaseRepresentation
bin1100000010000110000…
…00101011100000100101
31110112011102101121111112
412001003000223200211
523233211411041401
6513533205514405
741604312316523
oct6010300534045
91415142347445
10413441112101
1114a380802906
1268164712a05
132ccab217404
1416021355313
15ab4b9303bb
hex604302b825

413441112101 has 2 divisors, whose sum is σ = 413441112102. Its totient is φ = 413441112100.

The previous prime is 413441112067. The next prime is 413441112103. The reversal of 413441112101 is 101211144314.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 413286979876 + 154132225 = 642874^2 + 12415^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-413441112101 is a prime.

Together with 413441112103, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (413441112103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206720556050 + 206720556051.

It is an arithmetic number, because the mean of its divisors is an integer number (206720556051).

Almost surely, 2413441112101 is an apocalyptic number.

It is an amenable number.

413441112101 is a deficient number, since it is larger than the sum of its proper divisors (1).

413441112101 is an equidigital number, since it uses as much as digits as its factorization.

413441112101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 413441112101 its reverse (101211144314), we get a palindrome (514652256415).

The spelling of 413441112101 in words is "four hundred thirteen billion, four hundred forty-one million, one hundred twelve thousand, one hundred one".