Base | Representation |
---|---|
bin | 10010110101001110100101… |
… | …00100010001000110000111 |
3 | 12102121212211120020110020012 |
4 | 21122213102210101012013 |
5 | 20411440331440021203 |
6 | 224024032211300435 |
7 | 11502603632520524 |
oct | 1132472244210607 |
9 | 172555746213205 |
10 | 41411312423303 |
11 | 122164912aa429 |
12 | 47899588aa71b |
13 | 1a150baa56624 |
14 | a3246528014b |
15 | 4bc30b080bd8 |
hex | 25a9d2911187 |
41411312423303 has 2 divisors, whose sum is σ = 41411312423304. Its totient is φ = 41411312423302.
The previous prime is 41411312423227. The next prime is 41411312423357. The reversal of 41411312423303 is 30332421311414.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 41411312423303 - 230 = 41410238681479 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 41411312423303.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41411312423003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20705656211651 + 20705656211652.
It is an arithmetic number, because the mean of its divisors is an integer number (20705656211652).
Almost surely, 241411312423303 is an apocalyptic number.
41411312423303 is a deficient number, since it is larger than the sum of its proper divisors (1).
41411312423303 is an equidigital number, since it uses as much as digits as its factorization.
41411312423303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 32.
Adding to 41411312423303 its reverse (30332421311414), we get a palindrome (71743733734717).
The spelling of 41411312423303 in words is "forty-one trillion, four hundred eleven billion, three hundred twelve million, four hundred twenty-three thousand, three hundred three".
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